Egészítse ki a 2 bites komparátor igazságtáblázatát!
B1 | A1 | B0 | A0 | KB0A0=B1A1 |
0 | 0 | 0 | 0 | 1 |
0 | 0 | 0 | 1 | 0 |
0 | 0 | 1 | 0 | 0 |
0 | 0 | 1 | 1 | 0 |
0 | 1 | 0 | 0 | 0 |
0 | 1 | 0 | 1 | 1 |
0 | 1 | 1 | 0 | 0 |
0 | 1 | 1 | 1 | 0 |
1 | 0 | 0 | 0 | |
1 | 0 | 0 | 1 | |
1 | 0 | 1 | 0 | |
1 | 0 | 1 | 1 | |
1 | 1 | 0 | 0 | |
1 | 1 | 0 | 1 | |
1 | 1 | 1 | 0 | |
1 | 1 | 1 | 1 |